Question
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6. \( \left(\frac{a}{4}-4\right)\left(\frac{a^{2}}{16}+a+16\right) \)

Ask by Carroll Parry. in South Africa
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The expression simplifies to \( \frac{a^{3}-4096}{64} \).

Solution

Calculate or simplify the expression \( (a/4-4)*(a^2/16+a+16) \). Simplify the expression by following steps: - step0: Solution: \(\left(\frac{a}{4}-4\right)\left(\frac{a^{2}}{16}+a+16\right)\) - step1: Subtract the terms: \(\frac{a-16}{4}\times \left(\frac{a^{2}}{16}+a+16\right)\) - step2: Add the terms: \(\frac{a-16}{4}\times \frac{a^{2}+16a+256}{16}\) - step3: Multiply the terms: \(\frac{\left(a-16\right)\left(a^{2}+16a+256\right)}{4\times 16}\) - step4: Multiply the terms: \(\frac{\left(a-16\right)\left(a^{2}+16a+256\right)}{64}\) - step5: Simplify the product: \(\frac{a^{3}-4096}{64}\) The expression \( \left(\frac{a}{4}-4\right)\left(\frac{a^{2}}{16}+a+16\right) \) simplifies to \( \frac{a^{3}-4096}{64} \).

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Bonus Knowledge

To factor the expression \( \left(\frac{a}{4}-4\right)\left(\frac{a^{2}}{16}+a+16\right) \), we can first simplify our approach by rewriting the first part. The term \( \frac{a}{4} - 4 \) can be expressed as \( \frac{a - 16}{4} \). For the second term, we can observe that \( \frac{a^{2}}{16} + a + 16 \) is quadratic in form. To make factoring easier, let's first multiply it by \( 16 \) (the denominator of the leading term) to obtain: \[ a^{2} + 16a + 256 \] Now, we can factor this quadratic expression. The expression \( a^2 + 16a + 256 \) factors as \( (a+16)(a+16) \) or \( (a+16)^2 \). Putting it all together, we have: \[ \left(\frac{a - 16}{4}\right)\left((a + 16)^2\right) \] This can be simplified further as: \[ \frac{(a - 16)(a + 16)^2}{4} \] And that's the final factored form! As a recap, we ended up breaking it down into manageable parts to see the factoring opportunities that lay within the expression.

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