Question
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Izračunaj: a) \( \frac{1}{2}+\frac{1}{4} \), b) \( \frac{1}{6}+\frac{1}{2} \) C) \( \frac{1}{3}+\frac{1}{6} \) d) \( \frac{1}{4}+\frac{1}{8} \), e) \( \frac{1}{10}+\frac{1}{2} \), \( \frac{1}{4}+\frac{1}{12} \). Izračunaj: a) \( 0.5-\frac{1}{4} \) b) \( \frac{1}{3}-\frac{1}{6}, \quad \) d \( 0.25-\frac{1}{8} \) d) \( \frac{1}{3}-\frac{1}{9} \). (e) \( \frac{10}{12}-\frac{1}{3} \), f) \( \frac{5}{8}-\frac{1}{2} \)

Ask by Stewart Tucker. in Croatia
Jan 23,2025

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Answer

a) \( \frac{1}{2} + \frac{1}{4} = \frac{3}{4} \) b) \( \frac{1}{6} + \frac{1}{2} = \frac{2}{3} \) c) \( \frac{1}{3} + \frac{1}{6} = \frac{1}{2} \) d) \( \frac{1}{4} + \frac{1}{8} = \frac{3}{8} \) e) \( \frac{1}{10} + \frac{1}{2} = \frac{3}{5} \) i \( \frac{1}{4} + \frac{1}{12} = \frac{1}{3} \) a) \( 0.5 - \frac{1}{4} = \frac{1}{4} \) b) \( \frac{1}{3} - \frac{1}{6} = \frac{1}{6} \) c) \( 0.25 - \frac{1}{8} = \frac{1}{8} \) d) \( \frac{1}{3} - \frac{1}{9} = \frac{2}{9} \) e) \( \frac{10}{12} - \frac{1}{3} = \frac{1}{2} \) f) \( \frac{5}{8} - \frac{1}{2} = \frac{1}{8} \)

Solution

Naravno, izračunat ću sve zadane operacije korak po korak. ### Zbrojevi **a) \( \frac{1}{2} + \frac{1}{4} \)** Prvo pronađemo zajednički nazivnik, koji je 4. \[ \frac{1}{2} = \frac{2}{4} \] Sada zbrojimo: \[ \frac{2}{4} + \frac{1}{4} = \frac{3}{4} \] **b) \( \frac{1}{6} + \frac{1}{2} \)** Zajednički nazivnik je 6. \[ \frac{1}{2} = \frac{3}{6} \] Zbroj: \[ \frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3} \] **c) \( \frac{1}{3} + \frac{1}{6} \)** Zajednički nazivnik je 6. \[ \frac{1}{3} = \frac{2}{6} \] Zbroj: \[ \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \] **d) \( \frac{1}{4} + \frac{1}{8} \)** Zajednički nazivnik je 8. \[ \frac{1}{4} = \frac{2}{8} \] Zbroj: \[ \frac{2}{8} + \frac{1}{8} = \frac{3}{8} \] **e) \( \frac{1}{10} + \frac{1}{2} \) i \( \frac{1}{4} + \frac{1}{12} \)** Za \( \frac{1}{10} + \frac{1}{2} \): Zajednički nazivnik je 10. \[ \frac{1}{2} = \frac{5}{10} \] Zbroj: \[ \frac{1}{10} + \frac{5}{10} = \frac{6}{10} = \frac{3}{5} \] Za \( \frac{1}{4} + \frac{1}{12} \): Zajednički nazivnik je 12. \[ \frac{1}{4} = \frac{3}{12} \] Zbroj: \[ \frac{3}{12} + \frac{1}{12} = \frac{4}{12} = \frac{1}{3} \] ### Razlike **a) \( 0.5 - \frac{1}{4} \)** Pretvorimo 0.5 u razlomak: \[ 0.5 = \frac{1}{2} \] Zajednički nazivnik je 4. \[ \frac{1}{2} = \frac{2}{4} \] Razlika: \[ \frac{2}{4} - \frac{1}{4} = \frac{1}{4} \] **b) \( \frac{1}{3} - \frac{1}{6} \)** Zajednički nazivnik je 6. \[ \frac{1}{3} = \frac{2}{6} \] Razlika: \[ \frac{2}{6} - \frac{1}{6} = \frac{1}{6} \] **c) \( 0.25 - \frac{1}{8} \)** Pretvorimo 0.25 u razlomak: \[ 0.25 = \frac{1}{4} \] Zajednički nazivnik je 8. \[ \frac{1}{4} = \frac{2}{8} \] Razlika: \[ \frac{2}{8} - \frac{1}{8} = \frac{1}{8} \] **d) \( \frac{1}{3} - \frac{1}{9} \)** Zajednički nazivnik je 9. \[ \frac{1}{3} = \frac{3}{9} \] Razlika: \[ \frac{3}{9} - \frac{1}{9} = \frac{2}{9} \] **e) \( \frac{10}{12} - \frac{1}{3} \)** Pretvorimo \( \frac{1}{3} \) u nazivnik 12: \[ \frac{1}{3} = \frac{4}{12} \] Razlika: \[ \frac{10}{12} - \frac{4}{12} = \frac{6}{12} = \frac{1}{2} \] **f) \( \frac{5}{8} - \frac{1}{2} \)** Zajednički nazivnik je 8. \[ \frac{1}{2} = \frac{4}{8} \] Razlika: \[ \frac{5}{8} - \frac{4}{8} = \frac{1}{8} \]

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a) \( \frac{1}{2} + \frac{1}{4} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4} \) b) \( \frac{1}{6} + \frac{1}{2} = \frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3} \) c) \( \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \) d) \( \frac{1}{4} + \frac{1}{8} = \frac{2}{8} + \frac{1}{8} = \frac{3}{8} \) e) \( \frac{1}{10} + \frac{1}{2} = \frac{1}{10} + \frac{5}{10} = \frac{6}{10} = \frac{3}{5} \) \( \frac{1}{4} + \frac{1}{12} = \frac{3}{12} + \frac{1}{12} = \frac{4}{12} = \frac{1}{3} \) --- a) \( 0.5 - \frac{1}{4} = \frac{1}{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4} \) b) \( \frac{1}{3} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} = \frac{1}{6} \) c) \( 0.25 - \frac{1}{8} = \frac{1}{4} - \frac{1}{8} = \frac{2}{8} - \frac{1}{8} = \frac{1}{8} \) d) \( \frac{1}{3} - \frac{1}{9} = \frac{3}{9} - \frac{1}{9} = \frac{2}{9} \) e) \( \frac{10}{12} - \frac{1}{3} = \frac{10}{12} - \frac{4}{12} = \frac{6}{12} = \frac{1}{2} \) f) \( \frac{5}{8} - \frac{1}{2} = \frac{5}{8} - \frac{4}{8} = \frac{1}{8} \)

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