6. \( 2 \frac{2}{3}+1 \frac{4}{9}=2-1 \frac{4}{9}= \)
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To solve \( 2 \frac{2}{3} + 1 \frac{4}{9} \), we first convert the mixed numbers to improper fractions. \( 2 \frac{2}{3} = \frac{8}{3} \) and \( 1 \frac{4}{9} = \frac{13}{9} \). To add them, we need a common denominator, which is 9. Thus, convert \( \frac{8}{3} \) to \( \frac{24}{9} \). Now, \( \frac{24}{9} + \frac{13}{9} = \frac{37}{9} \). Next, we evaluate \( 2 - 1 \frac{4}{9} \). Conversion gives us \( 2 = \frac{18}{9} \) and \( 1 \frac{4}{9} = \frac{13}{9} \). So, \( \frac{18}{9} - \frac{13}{9} = \frac{5}{9} \). Therefore, \( 2 \frac{2}{3} + 1 \frac{4}{9} = \frac{37}{9} \) and \( 2 - 1 \frac{4}{9} = \frac{5}{9} \). The result of the original equation is \( \frac{37}{9} \) and \( \frac{5}{9} \).