966 2) Mary's parents ask her to pick up as many boxes of shoes as she can. Each box is $$ 12^{\prime \prime} imes 8^{\prime \prime} imes 6^{\prime \prime} $$ (volume: 576 cu in). If Mary used volume as an estimate, how many boxes would fit, if her trunk is 44 wide $$ imes 46^{\prime \prime} $$ long $$ imes 20^{\prime \prime} $$ tall (volume: 40,480 cu in)? 7 boxes 70 boxes 70.3 boxes

Question

966 2) Mary's parents ask her to pick up as many boxes of shoes as she can. Each box is $$ 12^{\prime \prime} 	imes 8^{\prime \prime} 	imes 6^{\prime \prime} $$ (volume: 576 cu in). If Mary used volume as an estimate, how many boxes would fit, if her trunk is 44 wide $$ 	imes 46^{\prime \prime} $$ long $$ 	imes 20^{\prime \prime} $$ tall (volume: 40,480 cu in)? 7 boxes 70 boxes 70.3 boxes

UpStudy AI · Accepted Answer

To determine how many boxes of shoes Mary can fit in her trunk using volume as an estimate, we first need to calculate the volume of both the trunk and the boxes.

1. **Volume of one box of shoes:**
   $$
   \text{Volume of one box} = 12^{\prime\prime} \times 8^{\prime\prime} \times 6^{\prime\prime} = 576 \text{ cu in}
   $$

2. **Volume of the trunk:**
   $$
   \text{Volume of the trunk} = 44^{\prime\prime} \times 46^{\prime\prime} \times 20^{\prime\prime} = 40,480 \text{ cu in}
   $$

3. **Calculating how many boxes can fit in the trunk:**
   $$
   \text{Number of boxes} = \frac{\text{Volume of the trunk}}{\text{Volume of one box}} = \frac{40,480 \text{ cu in}}{576 \text{ cu in}} \approx 70.3
   $$

Since Mary cannot fit a fraction of a box, we round down to the nearest whole number. Therefore, the maximum number of boxes that can fit in the trunk is **70 boxes**.

So the answer is **70 boxes**.
The maximum number of boxes that can fit in the trunk is 70 boxes.

Real Tutor Solution

Answer

Solution

Bonus Knowledge

Related Questions

Latest Arithmetic Questions