7. 15 grams of Li is placed into a 500 gram copper calorimeter containing 150 grams of water. The calorimeter experiences a temperature change of 20 degrees Celsius. $$ \begin{array}{ll}15 & ext { a) Determine the energy produced by this sample. }\end{array} $$

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7. 15 grams of Li is placed into a 500 gram copper calorimeter containing 150 grams of water. The calorimeter experiences a temperature change of 20 degrees Celsius. $$ \begin{array}{ll}15 & 	ext { a) Determine the energy produced by this sample. }\end{array} $$

UpStudy AI · Accepted Answer

To determine the energy produced by the 15 grams of lithium (Li) when it reacts in the calorimeter, we'll use the principle of **calorimetry**. Calorimetry involves measuring the heat transfer associated with a chemical reaction.

### Given:
- **Mass of Li (Lithium):** 15 grams
- **Mass of Copper Calorimeter:** 500 grams
- **Mass of Water:** 150 grams
- **Temperature Change ($$ \Delta T $$):** 20°C

### Constants:
- **Specific Heat Capacity of Water ($$ c_{\text{water}} $$):** 4.184 J/g°C
- **Specific Heat Capacity of Copper ($$ c_{\text{copper}} $$):** 0.385 J/g°C

### Steps to Calculate the Energy Produced:

1. **Calculate the Heat Absorbed by Water ($$ Q_{\text{water}} $$):**
   $$
   Q_{\text{water}} = \text{mass}_{\text{water}} \times c_{\text{water}} \times \Delta T
   $$
   $$
   Q_{\text{water}} = 150\, \text{g} \times 4.184\, \text{J/g°C} \times 20°C = 12,552\, \text{J}
   $$

2. **Calculate the Heat Absorbed by the Copper Calorimeter ($$ Q_{\text{copper}} $$):**
   $$
   Q_{\text{copper}} = \text{mass}_{\text{copper}} \times c_{\text{copper}} \times \Delta T
   $$
   $$
   Q_{\text{copper}} = 500\, \text{g} \times 0.385\, \text{J/g°C} \times 20°C = 3,850\, \text{J}
   $$

3. **Total Heat (Energy) Produced by the Reaction ($$ Q_{\text{total}} $$):**
   $$
   Q_{\text{total}} = Q_{\text{water}} + Q_{\text{copper}}
   $$
   $$
   Q_{\text{total}} = 12,552\, \text{J} + 3,850\, \text{J} = 16,402\, \text{J}
   $$

### Final Answer:
**The energy produced by the 15 grams of lithium is approximately 1.64 × 10⁴ joules (16.4 kJ).**
The energy produced by the 15 grams of lithium is approximately 16,402 joules.

15 grams of Li is placed into a 500 gram copper calorimeter containing 150 grams of water. The
calorimeter experiences a temperature change of 20 degrees Celsius.

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