Points: 0 of 1 Save Use the spinner shown. It is equally probable that the pointer will land on any one of the six regions. If the pointer lands on a borderline, spin again. If the pointer is spun twice, find the probability that it will land on blue and then blue. Find the probability that the spinner will land on blue and then blue. The probability is \( \square \) . (Type an integer or a simplified fraction.)

To find the probability that the spinner will land on blue and then blue, we need to consider the probability of landing on blue in the first spin and then landing on blue again in the second spin. Given that the spinner is equally probable for any one of the six regions, the probability of landing on blue in the first spin is \( \frac{1}{6} \). Since the pointer lands on a borderline, we need to spin again. Therefore, the probability of landing on blue in the second spin is also \( \frac{1}{6} \). To find the probability of both events happening (landing on blue in the first spin and then landing on blue in the second spin), we multiply the probabilities of each event: \[ P(\text{blue and then blue}) = P(\text{blue in first spin}) \times P(\text{blue in second spin}) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \] Therefore, the probability that the spinner will land on blue and then blue is \( \frac{1}{36} \).