A line's equation is given in point-slope form: $$ y=-2(x+5)+12 $$ This line's slope is A point on this line that is apparent from the given equation is

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To analyze the given linear equation in point-slope form:

$$
y = -2(x + 5) + 12
$$

**1. Determining the Slope:**

The general point-slope form of a linear equation is:

$$
y = m(x - x_1) + y_1
$$

where:
- $$ m $$ is the slope of the line.
- $$ (x_1, y_1) $$ is a specific point on the line.

Comparing the given equation to the general form:

$$
y = -2(x + 5) + 12 \
\Rightarrow y = -2(x - (-5)) + 12
$$

Here, the coefficient of $$ (x + 5) $$ is **$$-2$$**, which represents the **slope** of the line.

**2. Identifying a Point on the Line:**

From the comparison above:

$$
(x_1, y_1) = (-5, 12)
$$

This means that the point **$$(-5, 12)$$** lies on the line.

**Summary:**
- **Slope:** $$-2$$
- **Point on the Line:** $$(-5, 12)$$

Answer:
- The slope of the line is –2.
- A point on the line is ( –5, 12 ).
The slope of the line is –2, and a point on the line is (–5, 12).

A line’s equation is given in point-slope form:

This line’s slope is
A point on this line that is apparent from the given equation is

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A line’s equation is given in point-slope form: This line’s slope is A point on this line that is apparent from the given equation is