A line's equation is given in point-slope form: \( y=-2(x+5)+12 \) This line's slope is A point on this line that is apparent from the given equation is

The slope of the line can be directly identified from the point-slope form \( y - y_1 = m(x - x_1) \). Here, \( m = -2 \), which means the line is descending at a rate of 2 units down for every 1 unit it moves to the right. To find a point on this line, we can use the given equation. By substituting \( x = -5 \) (the x-coordinate from the equation), we can calculate \( y \): \( y = -2(-5 + 5) + 12 \), which simplifies to \( y = 12 \). Thus, the point (-5, 12) lies on the line!