Expand the expression to a polynomial in standard form: $$ \left(2 x^{2}+3 x+2\right)\left(2 x^{2}-3 x+6\right) $$

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Calculate the expanded algebra expression $$ (2x^2+3x+2)(2x^2-3x+6) $$.
Simplify the expression by following steps:
- step0: Multiply the terms:
  $$\left(2x^{2}+3x+2ight)\left(2x^{2}-3x+6ight)$$
- step1: Apply the distributive property:
  $$2x^{2}	imes 2x^{2}-2x^{2}	imes 3x+2x^{2}	imes 6+3x	imes 2x^{2}-3x	imes 3x+3x	imes 6+2	imes 2x^{2}-2	imes 3x+2	imes 6$$
- step2: Multiply the terms:
  $$4x^{4}-6x^{3}+12x^{2}+6x^{3}-9x^{2}+18x+4x^{2}-6x+12$$
- step3: Remove the opposites:
  $$4x^{4}+7x^{2}+12x+12$$
The expanded expression in standard form is $$4x^{4}+7x^{2}+12x+12$$.
The expanded expression is $$4x^{4}+7x^{2}+12x+12$$.

Expand the expression to a polynomial in standard form:

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