Question
lim_(x-> 7^{-}) f(x)=2 and lim_(x-> 7^{+}) f(x)=2, but f(7)=-2. What can you say about lim_(x->7)f(x)?
Ask by Schneider Harrington.
Mar 23,2025 20:18
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Answer
The function \( f(x) \) has a removable discontinuity at \( x=7 \) because the limit as \( x \) approaches 7 is 2, but \( f(7) \) is -2. To fix this, we can redefine \( f(7) \) to be 2.
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Beyond the Answer
In this scenario, we see an interesting feature of limits and continuity! The fact that \(\lim_{x \rightarrow 7} f(x) = 2\) and \(\lim_{x \rightarrow 7^{+}} f(x) = 2\) tells us that as \(x\) approaches 7 from the left or the right, the function \(f(x)\) is approaching 2. However, \(f(7) = -2\) indicates a discontinuity at that point, making \(f(x)\) not continuous at \(x = 7\). This is a classic example that shows limits can exist even when the function itself does not behave nicely at that point!
Understanding such cases helps solidify the concept of pointwise limits in real analysis. In real-world applications, similar behaviors can arise in systems where expected outcomes differ from actual results, such as in economic models or engineering simulations where certain inputs yield surprising outputs. For instance, a material might behave predictably under certain temperatures, but a specific threshold could cause a break in that expected behavior—akin to reaching your limit!
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