A car applies a force of 36.8 Newtons for a 668 -meter loop; what was the work done? (1 point) \( 24,600 \mathrm{~J} \) 705 J 18.2 J 0 J

To find the work done by the car, we can use the formula for work: \[ W = F \cdot d \cdot \cos(\theta) \] where: - \( W \) is the work done, - \( F \) is the force applied, - \( d \) is the distance over which the force is applied, - \( \theta \) is the angle between the force and the direction of motion. In this case, since the force is applied in the direction of the motion (assuming the loop is horizontal), the angle \( \theta \) is \( 0^\circ \). Therefore, \( \cos(0^\circ) = 1 \). Given: - \( F = 36.8 \, \text{N} \) - \( d = 668 \, \text{m} \) Now we can calculate the work done: \[ W = 36.8 \, \text{N} \cdot 668 \, \text{m} \cdot \cos(0^\circ) \] Let's calculate this. Calculate the value by following steps: - step0: Calculate: \(36.8\times 668\times 1\) - step1: Rewrite the expression: \(36.8\times 668\) - step2: Multiply the numbers: \(24582.4\) The calculation gives us: \[ W = 36.8 \, \text{N} \cdot 668 \, \text{m} = 24582.4 \, \text{J} \] Rounding this to the nearest whole number, we find: \[ W \approx 24582 \, \text{J} \] Among the options provided, the closest answer is \( 24,600 \, \text{J} \). Thus, the work done by the car is approximately \( 24,600 \, \text{J} \).