A car was valued at \( \$ 43,000 \) in the year 2009 . By 2013 , the car value had depreciated to \( \$ 17,000 \). If the car's value continues to drop by the same percentage, what will it be worth in 2018 ? Round to the nearest dollar.
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To find the car's value in 2018, we first need the annual depreciation rate between 2009 and 2013. In this period, the value dropped from \( \$ 43,000 \) to \( \$ 17,000 \). The formula for depreciation is: \[ V = P(1 - r)^t \] where: - \( V = \) final value, - \( P = \) initial value, - \( r = \) depreciation rate, - \( t = \) number of years. Plugging in the values: \[ 17000 = 43000(1 - r)^4 \] Dividing both sides by \( 43000 \): \[ \frac{17000}{43000} = (1 - r)^4 \] \[ 0.3953 \approx (1 - r)^4 \] Taking the fourth root: \[ 1 - r \approx 0.9031 \implies r \approx 0.0969 \text{ (or } 9.69\%) \] Now, we will calculate the car's worth in 2018, which is 5 years after 2013: \[ V_{2018} = 17000(1 - 0.0969)^5 \] Calculating: \[ V_{2018} \approx 17000(0.9031)^5 \approx 17000 \times 0.5905 \approx 10040.52 \] Rounding to the nearest dollar, the car's worth in 2018 will be approximately \( \$10,041 \).