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Solve the inequality. Write the solution set in interval notation. \( 11 \leq 6(n+4)-4 n \)

Ask by Sanders Bush. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

The solution is \( n \geq -\frac{13}{2} \), which in interval notation is \(\left[ -\frac{13}{2}, \infty \right)\).

Solution

To solve the inequality \( 11 \leq 6(n+4) - 4n \): 1. **Expand and simplify the right-hand side:** \[ 6(n + 4) - 4n = 6n + 24 - 4n = 2n + 24 \] 2. **Rewrite the inequality:** \[ 11 \leq 2n + 24 \] 3. **Isolate \( n \):** \[ 11 - 24 \leq 2n \quad \Rightarrow \quad -13 \leq 2n \] 4. **Divide both sides by 2:** \[ -\frac{13}{2} \leq n \] 5. **Express the solution in interval notation:** \[ \left[ -\frac{13}{2}, \infty \right) \] **Final Answer:** \(\left[ -\dfrac{13}{2},\ \infty\, \right)\)

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Beyond the Answer

Let's first simplify the inequality. Starting with: \[ 11 \leq 6(n+4) - 4n \] Distributing the 6 gives: \[ 11 \leq 6n + 24 - 4n \] Now, combine like terms: \[ 11 \leq 2n + 24 \] Next, we'll isolate \( n \) by subtracting 24 from both sides: \[ 11 - 24 \leq 2n \] \[ -13 \leq 2n \] Now, divide both sides by 2: \[ -\frac{13}{2} \leq n \] This can also be written as: \[ n \geq -\frac{13}{2} \] In interval notation, the solution set is: \[ \left[-\frac{13}{2}, \infty\right) \]

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