The function \( h(x)=\frac{1}{x-4} \) can be expressed in the form \( f(g(x)) \) where \( g(x)=(x-4) \) and \( f(x) \) is defined as: \( f(x)=\square \)

To express the function \( h(x)=\frac{1}{x-4} \) in the form \( f(g(x)) \) where \( g(x)=(x-4) \), we can see that \( h(x) \) takes the output of \( g(x) \) and applies a function \( f \) to it. Since \( g(x) = x - 4 \), then we can set \( y = g(x) \), which means \( y = x - 4 \). To find \( f(y) \), we need to evaluate \( h(x) \) when \( x = y + 4 \). Thus, \( h(y+4) = \frac{1}{y} \). Therefore, \( f(y) = \frac{1}{y} \). This leads us to conclude that: \( f(x) = \frac{1}{x} \)