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41) 2.3 A piece of ice falls off the side of a glacier and into the ocean. Its height above the ocean in meters can be modeled by the expression \( 33-4.9 t^{2} \), where \( t \) is the time in seconds after the plece of ice begins to fall. (i) What does the quantity \( 4.9 t^{2} \) represent in the expression? 4i) the height in meters of the piece of ice above the ocean after \( t \) seconds the time in seconds it takes for the piece of ice to reach a height of \( t \) meters the distance in meters the piece of ice has fallien after \( t \) seconds the time in scconds it takes for the pisce of ice to fall \( t \) meters

Ask by Weston Gibson. in the United States
Jan 22,2025

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Tutor-Verified Answer

Answer

\( 4.9t^{2} \) represents the distance in meters the piece of ice has fallen after \( t \) seconds.

Solution

The expression for the height of the ice above the ocean is given by: \[ \text{Height} = 33 - 4.9t^{2} \] Here, \( t \) represents the time in seconds after the piece of ice begins to fall. **Interpretation of \( 4.9t^{2} \):** In the context of kinematics, especially under the influence of gravity, the term \( \frac{1}{2}gt^{2} \) represents the distance an object has fallen after time \( t \), where \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^{2} \)). In this expression: \[ 4.9t^{2} = \frac{1}{2} \times 9.8 \times t^{2} \] Thus, \( 4.9t^{2} \) specifically represents the **distance** the piece of ice has fallen after \( t \) seconds. **Correct Option:** - **The distance in meters the piece of ice has fallen after \( t \) seconds** **Answer:** **The distance in meters the piece of ice has fallen after \( t \) seconds**

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Bonus Knowledge

The quantity \( 4.9 t^{2} \) in the expression represents the distance in meters that the piece of ice has fallen after \( t \) seconds. This comes from the physics of free fall, where distance traveled under constant acceleration (in this case, due to gravity) can be calculated using the formula \( d = \frac{1}{2}gt^2 \), and here, \( g \) is approximated as 9.8 m/s², thus leading to \( \frac{1}{2} \times 9.8 = 4.9 \). Now, if we picture this scenario, it’s quite a dramatic moment! Imagine that piece of ice, once nestled comfortably on the glacier, now breaking free and plummeting into the ocean. As it descends, that \( 4.9 t^{2} \) keeps track of its fall in a straight line, capturing the dance of gravity in action. It’s like watching a slow-motion replay of nature’s own action movie!

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