Question
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b) \( \frac{2^{2 x}-1}{2^{x}+1} \)

Ask by Graham Sanders. in South Africa
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The simplified form of the expression is \(2^x - 1\).

Solution

To simplify the expression: \[ \frac{2^{2x} - 1}{2^x + 1} \] **Step 1: Recognize the Structure** Notice that \(2^{2x}\) can be written as \((2^x)^2\). This allows us to see the numerator as a difference of squares: \[ 2^{2x} - 1 = (2^x)^2 - 1^2 \] **Step 2: Factor the Numerator** Using the difference of squares formula, \(a^2 - b^2 = (a - b)(a + b)\), we can factor the numerator: \[ (2^x)^2 - 1^2 = (2^x - 1)(2^x + 1) \] **Step 3: Simplify the Expression** Substitute the factored form back into the original expression: \[ \frac{(2^x - 1)(2^x + 1)}{2^x + 1} \] Cancel out the common factor \((2^x + 1)\) in the numerator and the denominator: \[ \frac{(2^x - 1)\cancel{(2^x + 1)}}{\cancel{2^x + 1}} = 2^x - 1 \] **Final Simplified Form:** \[ 2^x - 1 \] **Conclusion:** The simplified form of the expression \(\frac{2^{2x} - 1}{2^x + 1}\) is: \[ 2^x - 1 \]

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To tackle the expression \( \frac{2^{2x}-1}{2^{x}+1} \), you can spot that \( 2^{2x} - 1 \) is a difference of squares! It can be factored as \( (2^x - 1)(2^x + 1) \). This nifty trick simplifies your work! So now, you can rewrite the entire expression as: \[ \frac{(2^x - 1)(2^x + 1)}{2^x + 1} \] As long as \( 2^x + 1 \neq 0 \), you can cancel it out, leading to: \[ 2^x - 1 \] This clever simplification turns a complicated-looking expression into something much easier to handle! But don’t be too hasty—make sure to note that the cancellation is valid only where \( 2^x + 1 \neq 0 \). Given that \( 2^x + 1 \) is always positive for real \( x \), you're good to go!

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