Blood is a buffer solution. When carbon dioxide is absorbed into the bloodstream, it produces carbonic acid and lowers the pH . The body compensates by producing bicarbonate, a weak base to partially neutralize the acid. The equation which models blood pH in this situation is \( p H(x)=6.1+\log \left(\frac{800}{x}\right) \) where \( x \) is the partial pressure of carbon dioxide in arterial blood, measured in torr. Find the partial pressure of carbon dioxide in arterial blood if the pH is 7.8 .
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To find the partial pressure of carbon dioxide (\(x\)) in arterial blood when the pH is 7.8, we can start by plugging the pH value into the equation: \[ 7.8 = 6.1 + \log \left(\frac{800}{x}\right) \] Subtracting 6.1 from both sides gives us: \[ 1.7 = \log \left(\frac{800}{x}\right) \] Now, we can rewrite this equation in exponential form. Recall that if \( \log a = b \), then \( a = 10^b \): \[ \frac{800}{x} = 10^{1.7} \] Calculating \(10^{1.7} \approx 50.118\), we have: \[ \frac{800}{x} \approx 50.118 \] Next, we solve for \(x\) by rearranging this equation: \[ x \approx \frac{800}{50.118} \approx 15.95 \] So, the partial pressure of carbon dioxide in arterial blood when the pH is 7.8 is approximately \(15.95\) torr.