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a) \( \sqrt[a]{32 x^{2}}=2 x^{\frac{2}{b}} \)

Ask by Zimmerman Stanley. in South Africa
Jan 20,2025

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Answer

\( a = 5 \) and \( b = 5 \).

Solution

To solve the equation: \[ \sqrt[a]{32 x^{2}} = 2 x^{\frac{2}{b}} \] let's break it down step by step. ### Step 1: Rewrite the Radical as an Exponent The radical \(\sqrt[a]{32 x^{2}}\) can be rewritten using fractional exponents: \[ (32 x^2)^{1/a} = 2 x^{\frac{2}{b}} \] ### Step 2: Express Constants as Powers of 2 Notice that \(32\) is a power of \(2\): \[ 32 = 2^5 \] So, substitute this into the equation: \[ (2^5 x^2)^{1/a} = 2 x^{\frac{2}{b}} \] ### Step 3: Apply the Exponent to Both Terms Inside the Parenthesis Using the property \((ab)^c = a^c b^c\): \[ 2^{5/a} \cdot x^{2/a} = 2 \cdot x^{2/b} \] ### Step 4: Equate the Exponents of Like Bases Since the bases on both sides of the equation must be equal, their exponents must also be equal. **For the base 2:** \[ \frac{5}{a} = 1 \quad \Rightarrow \quad a = 5 \] **For the base \(x\):** \[ \frac{2}{a} = \frac{2}{b} \] Substitute \(a = 5\): \[ \frac{2}{5} = \frac{2}{b} \quad \Rightarrow \quad b = 5 \] ### Conclusion The values of \(a\) and \(b\) that satisfy the equation are both \(5\). \[ \boxed{a = 5,\ b = 5} \]

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To solve the equation \( \sqrt[a]{32 x^{2}}=2 x^{\frac{2}{b}} \), we can start by rewriting the left-hand side. The expression \( \sqrt[a]{32 x^{2}} \) can be transformed into \( (32 x^{2})^{\frac{1}{a}} \) or \( 32^{\frac{1}{a}} \cdot x^{\frac{2}{a}} \). This leads to the equation: \[ 32^{\frac{1}{a}} \cdot x^{\frac{2}{a}} = 2 x^{\frac{2}{b}} \] Next, let's focus on the numerical constants. We know that \( 32 = 2^5 \), so \( 32^{\frac{1}{a}} = (2^5)^{\frac{1}{a}} = 2^{\frac{5}{a}} \). Now we can rewrite our equation: \[ 2^{\frac{5}{a}} \cdot x^{\frac{2}{a}} = 2 x^{\frac{2}{b}} \] To simplify, we can equate the coefficients of \( 2 \) and \( x \) separately: 1. For the coefficients of \( 2 \): \[ \frac{5}{a} = 1 \quad \Rightarrow \quad a = 5 \] 2. For the coefficients of \( x \): \[ \frac{2}{a} = \frac{2}{b} \quad \Rightarrow \quad b = a = 5 \] Thus, the values of \( a \) and \( b \) are both \( 5 \).

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