\( 6.854 \div 5 \) Will there be a remainder? yes Divide to check.

When you divide \( 6.854 \) by \( 5 \), the operation looks like this: 1. Start with \( 6.854 \) and divide by \( 5 \). - \( 5 \) goes into \( 6 \) once: \( 1 \times 5 = 5 \) (remainder \( 1 \)). - Bring down the next digit, which is \( 8 \), making it \( 18 \). - \( 5 \) goes into \( 18 \) three times: \( 3 \times 5 = 15 \) (remainder \( 3 \)). - Bringing down \( 5 \) makes it \( 35 \). - \( 5 \) goes into \( 35 \) exactly seven times: \( 7 \times 5 = 35 \) (remainder \( 0 \)). - Finally, bring down \( 4 \), and \( 5 \) goes into \( 4 \) zero times. So, when you finish the division, you get \( 1.3708 \), and yes, there is indeed a remainder of \( 4 \).