Find the volume of a right circular cone that has a height of 18.8 m and a base with a radius of 19.3 m . Round your answer to the nearest tenth of a cubic meter. Answer Attempt 1 out of 2

To find the volume of a right circular cone, we can use the formula: \[ V = \frac{1}{3} \pi r^2 h \] where: - \( V \) is the volume of the cone, - \( r \) is the radius of the base of the cone, - \( h \) is the height of the cone. Given: - Height of the cone, \( h = 18.8 \) m, - Radius of the base of the cone, \( r = 19.3 \) m. Substitute the given values into the formula: \[ V = \frac{1}{3} \pi (19.3)^2 (18.8) \] Now, we can calculate the volume of the cone. Calculate the value by following steps: - step0: Calculate: \(\frac{1}{3}\pi \times 19.3^{2}\times 18.8\) - step1: Convert the expressions: \(\frac{1}{3}\pi \left(\frac{193}{10}\right)^{2}\times 18.8\) - step2: Multiply the terms: \(\frac{94}{15}\pi \left(\frac{193}{10}\right)^{2}\) - step3: Multiply: \(\frac{94\pi }{15}\left(\frac{193}{10}\right)^{2}\) - step4: Evaluate the power: \(\frac{94\pi }{15}\times \frac{193^{2}}{10^{2}}\) - step5: Rewrite the expression: \(\frac{2\times 47\pi }{15}\times \frac{193^{2}}{10^{2}}\) - step6: Rewrite the expression: \(\frac{2\times 47\pi }{15}\times \frac{193^{2}}{2^{2}\times 5^{2}}\) - step7: Reduce the numbers: \(\frac{47\pi }{15}\times \frac{193^{2}}{2\times 5^{2}}\) - step8: Multiply the fractions: \(\frac{47\pi \times 193^{2}}{15\times 50}\) - step9: Multiply: \(\frac{1750703\pi }{750}\) The volume of the right circular cone is approximately 7333.327578 cubic meters. Rounding to the nearest tenth of a cubic meter, the volume of the cone is approximately 7333.3 cubic meters.