Question
Solve this system of equations by graphing. First graph the equations, and then type the solution. \[ y=\frac{5}{2} x+1 \] \( x=-2 \) Click to select points on the graph.
Ask by Murphy Bush. in the United States
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The solution is \( (-2, -4) \).
Solution
To solve the system of equations by graphing, let's analyze each equation:
1. **First Equation:** \( y = \frac{5}{2}x + 1 \)
- This is a linear equation in slope-intercept form (\( y = mx + b \)) where:
- **Slope (m):** \( \frac{5}{2} \)
- **Y-intercept (b):** \( 1 \)
- **Graphing the First Equation:**
- Start by plotting the y-intercept at \( (0, 1) \).
- From the y-intercept, use the slope to find another point. Since the slope is \( \frac{5}{2} \), you can go up 5 units and right 2 units to reach the next point at \( (2, 6) \).
- Draw a straight line through these points.
2. **Second Equation:** \( x = -2 \)
- This is a vertical line where all points on the line have an x-coordinate of \( -2 \).
- **Graphing the Second Equation:**
- Draw a vertical line that crosses the x-axis at \( x = -2 \).
3. **Finding the Intersection:**
- The solution to the system is the point where the two graphs intersect.
- To find this, substitute \( x = -2 \) into the first equation to find the corresponding y-value:
\[
y = \frac{5}{2}(-2) + 1 = -5 + 1 = -4
\]
- So, the point of intersection is \( (-2, -4) \).
**Solution:** \( (-2,\, -4) \)
Reviewed and approved by the UpStudy tutoring team
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Mind Expander
To graph the equation \( y=\frac{5}{2} x+1 \), start by plotting the y-intercept (0,1) on the y-axis. Then find another point by choosing a value for \( x \); for example, when \( x=2 \), \( y=\frac{5}{2} \times 2 + 1 = 6 \), giving you the point (2,6). Now draw a line through those points. Next, for the line \( x=-2 \), plot a vertical line that crosses the x-axis at -2. The intersection of these two lines represents the solution. The solution to this system of equations is the point where the two graphs intersect, which is \((-2, 0)\).