66. The distance between the centers of the two oxygen atoms in an oxygen molecule is $$ 1.21 imes 10^{.3} \mathrm{~cm} $$. What is this distance in inches?

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66. The distance between the centers of the two oxygen atoms in an oxygen molecule is $$ 1.21 	imes 10^{.3} \mathrm{~cm} $$. What is this distance in inches?

UpStudy AI · Accepted Answer

To convert the distance between the centers of the two oxygen atoms in an oxygen molecule from centimeters (cm) to inches (in), follow these steps:

1. **Understand the Given Value:**
   
   The distance is given as $$ 1.21 \times 10^{-8} $$ cm. (Assuming the exponent is $$-8$$ based on typical bond lengths.)

2. **Conversion Factor:**
   
   $$ 1 \text{ inch} = 2.54 \text{ cm} $$

3. **Perform the Conversion:**
   
   $$
   \text{Distance in inches} = \frac{1.21 \times 10^{-8} \text{ cm}}{2.54 \text{ cm/in}} 
   $$
   
   $$
   \text{Distance in inches} \approx 4.764 \times 10^{-9} \text{ in}
   $$
   
   Rounding to two significant figures:

$$
   \text{Distance in inches} \approx 4.8 \times 10^{-9} \text{ in}
   $$

**Final Answer:**

The distance is approximately 4.8 × 10⁻⁹ inches.
The distance is approximately $$4.8 \times 10^{-9}$$ inches.

The distance between the centers of the two oxygen atoms in an oxygen molecule
is . What is this distance in inches?

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The distance between the centers of the two oxygen atoms in an oxygen molecule is . What is this distance in inches?