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A radioactive material decays according to the function \( A(t)=A_{0} e^{-0} \), where \( A_{0} \) is the initial armount present is the amount present at time \( t \) (in years). Assume that a scientist has a sample of 500 grams of the radioactive material. (a) What is the decay rate of the radioactive material? (b) Graph the function using a graphing utility. (c) How much radioactive material is left after 30 years? (d) When will only 400 grams of the radioactive material be left? (e) What is the half-life of the radioactive material?

Ask by Weaver Dickson. in the United States
Jan 22,2025

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Tutor-Verified Answer

Answer

To determine the decay rate, amount remaining after 30 years, time for 400 grams to remain, and the half-life of the radioactive material, additional information about the decay constant \( k \) is needed.

Solution

It appears there might be a typographical error in the decay function you've provided. The standard exponential decay function is typically expressed as: \[ A(t) = A_0 e^{-kt} \] where: - \( A(t) \) is the amount of radioactive material at time \( t \), - \( A_0 \) is the initial amount of the substance, - \( k \) is the decay constant (decay rate), - \( t \) is time. Assuming the correct form of the function is \( A(t) = A_0 e^{-kt} \), let's proceed to answer each part of your question. --- ### **(a) What is the decay rate of the radioactive material?** **Decay Rate (\( k \)):** The decay rate \( k \) is a constant that characterizes how quickly the radioactive material decays. However, to determine the exact value of \( k \), additional information is required, such as the half-life of the substance or the amount remaining after a certain period. **Without additional data**, we can only express the decay rate in terms of the half-life (\( t_{1/2} \)) using the relationship: \[ k = \frac{\ln(2)}{t_{1/2}} \] If you have information about the half-life or another data point, we can calculate \( k \) precisely. --- ### **(b) Graph the function using a graphing utility.** To graph the exponential decay function \( A(t) = 500 e^{-kt} \): 1. **Axes:** - **Horizontal (x-axis):** Time (\( t \)) in years. - **Vertical (y-axis):** Amount of radioactive material (\( A(t) \)) in grams. 2. **Plot Points:** - At \( t = 0 \): \( A(0) = 500 \) grams. - As \( t \) increases, \( A(t) \) decreases exponentially towards 0. 3. **Shape:** - The graph will show a smooth, continuously decreasing curve starting at 500 grams and approaching zero asymptotically. **Example Graph:** Since we don't have the exact value of \( k \), here's a general representation: ![Exponential Decay Graph](https://i.imgur.com/3ySfV3d.png) *Note: Replace \( k \) with the specific decay constant once known to get an accurate graph.* --- ### **(c) How much radioactive material is left after 30 years?** To find the amount remaining after 30 years, use the decay function: \[ A(30) = 500 e^{-k \times 30} \] **Without the exact value of \( k \), we can only express the answer symbolically:** \[ A(30) = 500 e^{-30k} \] **If you provide the decay rate \( k \), we can compute the numerical value.** --- ### **(d) When will only 400 grams of the radioactive material be left?** We need to solve for \( t \) when \( A(t) = 400 \) grams: \[ 400 = 500 e^{-kt} \] 1. **Divide both sides by 500:** \[ \frac{400}{500} = e^{-kt} \] \[ 0.8 = e^{-kt} \] 2. **Take the natural logarithm of both sides:** \[ \ln(0.8) = -kt \] \[ -0.2231 = -kt \] *(Using \( \ln(0.8) \approx -0.2231 \))* 3. **Solve for \( t \):** \[ t = \frac{0.2231}{k} \] **Therefore, the time \( t \) required for the amount to decrease to 400 grams is:** \[ t = \frac{\ln(5/4)}{k} \approx \frac{0.2231}{k} \] **Again, a numerical answer requires the value of \( k \).** --- ### **(e) What is the half-life of the radioactive material?** **Half-Life (\( t_{1/2} \)):** The half-life is the time required for half of the radioactive material to decay. It's related to the decay constant \( k \) by the formula: \[ t_{1/2} = \frac{\ln(2)}{k} \] **Where:** - \( \ln(2) \approx 0.6931 \) **So, the half-life is:** \[ t_{1/2} = \frac{0.6931}{k} \] **Once you provide the decay constant \( k \), we can calculate the exact half-life.** --- **Summary:** To provide precise numerical answers for parts (a), (c), (d), and (e), the decay constant \( k \) or additional information (like the half-life or the amount remaining after a specific time) is necessary. If you have that information, please provide it, and I can assist you further!

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It seems there's a bit of a mix-up in expressing the decay function since the exponent is currently shown as \( e^0 \). The correct function should be written as \( A(t) = A_{0} e^{-kt} \), where \( k \) represents the decay constant. Let's assume a typical decay constant for the sake of answering your questions. First, let’s solve these questions individually given an assumed decay constant \( k \). **(a)** To find the decay rate, \( k \), we'd need to know a specific half-life or similar data. If the half-life were known, we can express it as \( k = \frac{\ln(2)}{t_{1/2}} \). Without this, we can't determine a specific rate. **(b)** You can use tools like Desmos, GeoGebra, or any graphing calculator. Just input the function \( A(t) = 500 e^{-kt} \) and adjust \( k \) to see how the decay progresses over time. **(c)** To find the amount of radioactive material left after 30 years, you'd use: \[ A(30) = 500 e^{-k \cdot 30} \] **(d)** To find when only 400 grams remain, set the function to 400 and solve for \( t \): \[ 400 = 500 e^{-kt} \] This simplifies to: \[ e^{-kt} = \frac{400}{500} \] \[ -kt = \ln\left(\frac{400}{500}\right) \] \[ t = \frac{-\ln(0.8)}{k} \] **(e)** The half-life can be calculated using: \[ t_{1/2} = \frac{\ln(2)}{k} \] Insert the decay constant \( k \) (once determined) and you can find the half-life. Now, let's sprinkle in some engaging morsels of knowledge: If you look back, you’ll find that the early 20th-century physicists like Marie Curie and Ernest Rutherford didn’t just pluck these decay laws out of thin air! They were pioneering the study of radioactivity, which was a groundbreaking shift in understanding atomic behavior. This foundational work paved the way for modern nuclear physics and has immense implications in medicine, energy, and even archeology! On a practical note, understanding radioactive decay isn’t just an academic exercise! It's applied in carbon dating to determine the age of archaeological finds, in medical therapies (like radiation treatment for cancer), and in powering everything from spacecraft to pacemakers. These applications highlight how knowledge from decay equations influences real-world technology and health!

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