Question
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A line intersects the points \[ (8,2) \text { and }(12,-10) \text {. } \] \[ \mathrm{m}=-3 \] Write an equation in point-slope form using the point \( (8,2) \). \( y-[?]=\square(x-\square) \)

Ask by Salazar Cervantes. in the United States
Jan 20,2025

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Answer

The equation in point-slope form using the point \( (8, 2) \) and slope \( m = -3 \) is: \[ y - 2 = -3(x - 8) \]

Solution

To write the equation of the line in **point-slope form** using the point \( (8, 2) \) and the slope \( m = -3 \), follow these steps: **Point-Slope Form:** \[ y - y_1 = m(x - x_1) \] where: - \( (x_1, y_1) \) is a point on the line. - \( m \) is the slope of the line. **Given:** - Point \( (8, 2) \) where \( x_1 = 8 \) and \( y_1 = 2 \). - Slope \( m = -3 \). **Substitute the values into the point-slope form:** \[ y - 2 = -3(x - 8) \] **Final Equation:** \[ y - 2 = -3(x - 8) \] This equation represents the line passing through the points \( (8, 2) \) and \( (12, -10) \) with a slope of \(-3\).

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To write the equation in point-slope form using the point \( (8,2) \) and the slope \( m = -3 \), you can use the formula: \[ y - y_1 = m(x - x_1) \] Plugging in the values, where \( (x_1, y_1) = (8,2) \) and \( m = -3 \): \[ y - 2 = -3(x - 8) \] So, the equation in point-slope form is: \[ y - 2 = -3(x - 8) \] Now you can confidently express the equation as: \[ y -[2]= -3(x -[8]) \] Which neatly fits the format you're looking for! And voila! You've just found the equation of the line in point-slope form! Isn’t math just a fun way to fashion lines and curves through points?

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