Question 3: A straight line passes through $$ (-2,-3) $$ and has a gradient of 5 . The equation of the line $$ i $$

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To find the equation of a straight line that passes through the point $$(-2, -3)$$ with a gradient (slope) of $$5$$, we can use the **point-slope form** of a line equation:

$$
y - y_1 = m(x - x_1)
$$

Where:
- $$m$$ is the gradient.
- $$(x_1, y_1)$$ is the point the line passes through.

**Given:**
- Gradient ($$m$$) = $$5$$
- Point $$(x_1, y_1)$$ = $$(-2, -3)$$

**Plugging the values into the point-slope form:**

$$
y - (-3) = 5(x - (-2))
$$

Simplify the equation:

$$
y + 3 = 5(x + 2)
$$

Expand the right side:

$$
y + 3 = 5x + 10
$$

Subtract $$3$$ from both sides to solve for $$y$$:

$$
y = 5x + 10 - 3
$$
$$
y = 5x + 7
$$

**Final Equation of the Line:**

$$
y = 5x + 7
$$
The equation of the line is $$ y = 5x + 7 $$.

Question 3: A straight line passes through \( (-2,-3) \) and has a gradient of 5 . The equation of the line \( i \)

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