Question

\( 1 \frac{12 a^{0} b^{3} c^{-1}}{15 a^{-2} b^{5} c^{-3}} \)

Ask by Turner Peterson. in South Africa
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The simplified form of the expression is \(\frac{4c^{2}a^{2}}{5b^{2}}\).

Solution

Calculate or simplify the expression \( 1 \frac{12 a^{0} b^{3} c^{-1}}{15 a^{-2} b^{5} c^{-3}} \). Simplify the expression by following steps: - step0: Solution: \(\left(1\times \frac{12a^{0}b^{3}c^{-1}}{15a^{-2}b^{5}c^{-3}}\right)\) - step1: Evaluate: \(1\times \frac{12a^{0}b^{3}c^{-1}}{15a^{-2}b^{5}c^{-3}}\) - step2: Multiply by \(a^{-n}:\) \(1\times \frac{12a^{0}b^{3}c^{-1}a^{2}b^{-5}c^{3}}{15}\) - step3: Evaluate the power: \(1\times \frac{12\times 1\times b^{3}c^{-1}a^{2}b^{-5}c^{3}}{15}\) - step4: Reduce the fraction: \(1\times \frac{4b^{-2}c^{2}a^{2}}{5}\) - step5: Rewrite the expression: \(1\times \frac{4c^{2}a^{2}}{5b^{2}}\) - step6: Calculate: \(\frac{4c^{2}a^{2}}{5b^{2}}\) The simplified form of the expression \(1 \frac{12 a^{0} b^{3} c^{-1}}{15 a^{-2} b^{5} c^{-3}}\) is \(\frac{4c^{2}a^{2}}{5b^{2}}\).

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Mind Expander

To simplify the expression \( 1 \frac{12 a^{0} b^{3} c^{-1}}{15 a^{-2} b^{5} c^{-3}} \), first remember that any term raised to the zero power equals 1, so \( a^0 = 1 \). This reduces our expression to \( \frac{12 b^{3} c^{-1}}{15 a^{-2} b^{5} c^{-3}} \). Now, we can simplify the coefficients: \( \frac{12}{15} = \frac{4}{5} \). Next, apply the rules of exponents. For \( b^3 \) and \( b^5 \), we subtract the exponents: \( 3 - 5 = -2 \), giving us \( b^{-2} \). For \( c^{-1} \) and \( c^{-3} \), we again subtract the exponents: \( -1 - (-3) = 2 \), resulting in \( c^{2} \). Then, for \( a^{-2} \) in the denominator, it transforms into \( a^{2} \) when moved to the numerator. Thus, putting it all together, the simplified expression is: \[ \frac{4 c^{2}}{5 a^{2} b^{2}}. \]

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