Question
Graph the logarithmic function \( g(x)=-\log _{2} x+1 \). To do this, plot two points on the graph of the function, and also draw the asymptote. Then, click on the graph-a-function button. Additionally, give the domain and range of the function using interval notation.
Ask by Ross Rogers.
Nov 02,2024 23:58
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Answer
The domain is \( (0, \infty) \) and the range is \( (-\infty, +\infty) \).
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Beyond the Answer
To plot the logarithmic function \( g(x) = -\log_2 x + 1 \), let's start by determining two key points.
1. **Choosing values of \( x \)**:
- For \( x = 1 \):
\[
g(1) = -\log_2(1) + 1 = -0 + 1 = 1
\]
So the point is \( (1, 1) \).
- For \( x = 2 \):
\[
g(2) = -\log_2(2) + 1 = -1 + 1 = 0
\]
So the point is \( (2, 0) \).
2. **Asymptote**: Since the logarithmic function approaches negative infinity as \( x \) approaches 0 from the right, the vertical line \( x = 0 \) is a vertical asymptote.
Now, regarding the domain and range:
- **Domain**: The logarithmic function is defined for \( x > 0 \), so the domain in interval notation is \( (0, \infty) \).
- **Range**: Since the function goes to infinity as \( x \) increases (i.e., when \( x \) is larger), and approaches 1 as \( x \) approaches 0 from the right, the range in interval notation is \( (-\infty, 1) \).
Now you can go ahead and graph the function, plot the points \( (1, 1) \) and \( (2, 0) \), and remember to draw the vertical asymptote at \( x = 0 \). Happy graphing!
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