What is the current that Flows in a circuit When a 20 V battery is connected to the bulb of resistance 90 ?

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To determine the current flowing in the circuit, you can use **Ohm's Law**, which states:

$$ I = \frac{V}{R} $$

Where:
- $$ I $$ is the current (in amperes, A)
- $$ V $$ is the voltage (in volts, V)
- $$ R $$ is the resistance (in ohms, Ω)

**Given:**
- Voltage ($$ V $$) = 20 V
- Resistance ($$ R $$) = 90 Ω

**Calculation:**

$$ I = \frac{20\ \text{V}}{90\ \Omega} $$

$$ I \approx 0.222\ \text{A} $$

So, the current flowing through the circuit is approximately **0.222 amperes** (or **222 milliamperes**, mA).

**Summary:**
When a 20 V battery is connected to a bulb with a resistance of 90 Ω, the current flowing through the circuit is approximately **0.222 A**.
The current flowing through the circuit is approximately 0.222 amperes.

What is the current that Flows in a circuit When a 20 V battery is connected to the bulb of resistance 90 ?

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