Use properties of logarithms to evaluate the expression. \( \ln e^{-4}-\ln e^{-\frac{3}{4}} \)
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First, let's simplify each term using the property that \( \ln e^x = x \). So, \( \ln e^{-4} = -4 \) and \( \ln e^{-\frac{3}{4}} = -\frac{3}{4} \). Now, substituting these values into the expression, we get: \[ \ln e^{-4}-\ln e^{-\frac{3}{4}} = -4 - \left(-\frac{3}{4}\right) = -4 + \frac{3}{4} \] Next, we can convert -4 into a fraction to combine the two terms. Since -4 can be written as \(-\frac{16}{4}\), the expression becomes: \[ -\frac{16}{4} + \frac{3}{4} = -\frac{16 - 3}{4} = -\frac{13}{4} \] Thus, the final evaluation of the expression is: \[ \ln e^{-4}-\ln e^{-\frac{3}{4}} = -\frac{13}{4} \]