Question
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Determine the convergence or divergence of the sequence with the given \( n \)th term. If the sequence converges, find its limit. (If the quantity diverges, enter DIVERGES.) \[ a_{n}=\frac{6}{n+9} \]

Ask by Stephens Garrett. in the United States
Dec 18,2024

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Answer

The sequence converges and its limit is 0.

Solution

To determine whether the sequence \( a_n = \frac{6}{n+9} \) converges or diverges, and to find its limit if it converges, we analyze its behavior as \( n \) approaches infinity. 1. **Examine the Denominator:** - As \( n \) increases, \( n + 9 \) also increases without bound. Mathematically, \(\lim_{n \to \infty} (n + 9) = \infty\). 2. **Evaluate the Sequence:** - Since the denominator grows without bound, the overall fraction \( \frac{6}{n+9} \) becomes smaller and smaller. - Mathematically, \(\lim_{n \to \infty} \frac{6}{n+9} = 0\). 3. **Conclusion:** - The sequence converges because it approaches a specific finite limit. - The limit of the sequence is **0**. **Answer:** The sequence converges and its limit is 0

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Beyond the Answer

To determine the convergence of the sequence \( a_{n}=\frac{6}{n+9} \), we need to analyze what happens to \( a_{n} \) as \( n \) approaches infinity. As \( n \) increases, the denominator \( n + 9 \) grows larger and larger. Consequently, the fraction as a whole approaches zero. Therefore, the limit of the sequence is: \[ \lim_{n \to \infty} a_{n} = \lim_{n \to \infty} \frac{6}{n+9} = 0. \] Thus, the sequence converges, and its limit is \( 0 \).

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