Question

A rectangle has its vertices at the following coordinates: \(A(1, 2)\), \(B(1, 5)\), \(C(4, 5)\), and \(D(4, 2)\). What are the coordinates of the center of the rectangle?

Ask by Wood Christensen. in Greece
Jan 18,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The center of the rectangle is at \(\left(2.5, 3.5\right)\).

Solution

To find the center of the rectangle with vertices at \(A(1, 2)\), \(B(1, 5)\), \(C(4, 5)\), and \(D(4, 2)\), we can calculate the midpoint of one of the diagonals. Let's use the diagonal from \(A\) to \(C\): - Coordinates of \(A\): \((1, 2)\) - Coordinates of \(C\): \((4, 5)\) The midpoint \(M\) of diagonal \(AC\) is calculated as: \[ M = \left( \frac{1 + 4}{2}, \frac{2 + 5}{2} \right) = \left( \frac{5}{2}, \frac{7}{2} \right) = \left(2.5, 3.5\right) \] Alternatively, using the diagonal from \(B\) to \(D\): - Coordinates of \(B\): \((1, 5)\) - Coordinates of \(D\): \((4, 2)\) The midpoint \(M\) of diagonal \(BD\) is also: \[ M = \left( \frac{1 + 4}{2}, \frac{5 + 2}{2} \right) = \left( \frac{5}{2}, \frac{7}{2} \right) = \left(2.5, 3.5\right) \] Therefore, the coordinates of the center of the rectangle are: \(\boxed{\left(\dfrac{5}{2},\ \dfrac{7}{2}\right)}\)

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Mind Expander

To find the center of the rectangle, you can calculate the midpoint of the diagonals. The diagonals of the rectangle are AC and BD. The coordinates of points A and C are \(A(1, 2)\) and \(C(4, 5)\). The midpoint of AC can be found using the formula \((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\): \[ \text{Midpoint of AC} = \left(\frac{1 + 4}{2}, \frac{2 + 5}{2}\right) = \left(\frac{5}{2}, \frac{7}{2}\right) = (2.5, 3.5) \] Similarly, the coordinates of points B and D are \(B(1, 5)\) and \(D(4, 2)\). The midpoint of BD is: \[ \text{Midpoint of BD} = \left(\frac{1 + 4}{2}, \frac{5 + 2}{2}\right) = \left(\frac{5}{2}, \frac{7}{2}\right) = (2.5, 3.5) \] Thus, the coordinates of the center of the rectangle are \( (2.5, 3.5) \).

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