Question
upstudy study bank question image url

A new residential subdivision is estimated to have a peak sewage flow rate \( (\mathrm{Q}) \) of \( 0.2474 \mathrm{~m}^{3} / \mathrm{s} \). The proposed concrete wastewater sewer carrying sewage from the subdivision drops 0.622 m in elevation over a distance of 285 m to connect to a larger sanitary trunk sewer. Determine the EXACT diameter in mm (accurate to the nearest mm ) of sewer pipe required to carry this wastewater.

Ask by Pritchard Mcfarlane. in Canada
Dec 09,2024

Real Tutor Solution

Tutor-Verified Answer

Answer

The diameter of the sewer pipe required is approximately 63 mm.

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

Extra Insights

To determine the diameter of the sewer pipe required to carry the wastewater, we can use the Manning's equation, which is a widely accepted empirical formula for calculating the flow of water in open channels and pipes. For a circular pipe flowing full, Manning’s equation is expressed as: \[ Q = \frac{1}{n} A R^{2/3} S^{1/2} \] Where: - \( Q \) is the flow rate (m³/s), - \( n \) is the Manning's roughness coefficient (commonly between 0.012 and 0.015 for concrete), - \( A \) is the cross-sectional area of the pipe (m²), - \( R \) is the hydraulic radius (m), and - \( S \) is the slope of the energy grade line (for a circular pipe, it’s the same as the slope of the pipe which can be derived from the drop and length). 1. **Calculate the slope \( S \)**: \[ S = \frac{h}{L} = \frac{0.622 \, \text{m}}{285 \, \text{m}} \approx 0.00218 \] 2. **Assume a circular pipe of diameter \( D \)**: The Area \( A \) in terms of \( D \) is \( A = \frac{\pi D^2}{4} \), and the hydraulic radius \( R = \frac{A}{P}\), where \( P = \pi D \). Therefore, \[ R = \frac{\frac{\pi D^2}{4}}{\pi D} = \frac{D}{4} \] 3. **Substituting into Manning’s equation**, we rearrange: \[ 0.2474 = \frac{1}{n} \left( \frac{\pi D^2}{4} \right) \left( \frac{D}{4} \right)^{2/3} S^{1/2} \] 4. **Plug in values** assuming \( n \) (for concrete) is around 0.013: \[ 0.2474 = \frac{1}{0.013} \left( \frac{\pi D^2}{4} \right) \left( \frac{D}{4} \right)^{2/3} (0.00218)^{1/2} \] 5. **Solve for \( D \)**: This requires iterative calculations or numerical methods, ultimately leading to a Diameter \( D \approx 0.276 \) m which converts to \( D = 276 \) mm. Thus, the exact diameter of the sewer pipe required to carry this wastewater is approximately **276 mm**. --- From the ambitious journey of pipe sizing to ensure efficient wastewater flow, it’s important to highlight that the sizing of pipes not only saves us from costly overflow situations but is also crucial for preventing sewer blockages that lead to nasty surprises! And remember, a well-designed sewer system is not just a matter of numbers; it's about maintaining public health and environmental safety. So always double-check your calculations and consider all factors such as peak flow rates and maintenance access when planning!

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy