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\( \mathrm{J}(-7,7) \) Write an algebraic representation for the reflec

Ask by Lyons Wade. in the United States
Jan 22,2025

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Answer

To reflect the point \( J(-7, 7) \) across an axis or line, use the following rules: 1. **Across the x-axis:** \( J' = (-7, -7) \) 2. **Across the y-axis:** \( J' = (7, 7) \) 3. **Across the line \( y = x \):** \( J' = (7, -7) \) 4. **Across the origin:** \( J' = (7, -7) \) Choose the rule that matches the reflection you want.

Solution

To create an algebraic representation for the reflection of the point \( J(-7, 7) \), we first need to specify **across which axis or line** the reflection is taking place. Common reflections include: 1. **Reflection Across the x-axis:** - **Rule:** \( (x, y) \rightarrow (x, -y) \) - **Application to \( J(-7, 7) \):** \[ J' = (-7, -7) \] - **Explanation:** Only the y-coordinate changes its sign, flipping the point over the x-axis. 2. **Reflection Across the y-axis:** - **Rule:** \( (x, y) \rightarrow (-x, y) \) - **Application to \( J(-7, 7) \):** \[ J' = (7, 7) \] - **Explanation:** Only the x-coordinate changes its sign, flipping the point over the y-axis. 3. **Reflection Across the Line \( y = x \):** - **Rule:** \( (x, y) \rightarrow (y, x) \) - **Application to \( J(-7, 7) \):** \[ J' = (7, -7) \] - **Explanation:** The x and y coordinates are swapped, reflecting the point over the line \( y = x \). 4. **Reflection Across the Origin (Point Reflection):** - **Rule:** \( (x, y) \rightarrow (-x, -y) \) - **Application to \( J(-7, 7) \):** \[ J' = (7, -7) \] - **Explanation:** Both coordinates change their signs, effectively rotating the point 180 degrees around the origin. **Example: Reflection Across the x-axis** Given the point \( J(-7, 7) \), reflecting it across the x-axis: \[ J' = (-7, -7) \] **Algebraic Representation:** \[ (x, y) \rightarrow (x, -y) \] This represents the general rule for reflecting any point across the x-axis. --- **Choose the appropriate reflection rule based on the desired axis or line of reflection.**

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Beyond the Answer

To reflect the point \( J(-7, 7) \) over the x-axis, you simply change the sign of the y-coordinate. The new point would then be \( J'(-7, -7) \). If you want to reflect over the y-axis, you change the sign of the x-coordinate, resulting in the point \( J''(7, 7) \). Both reflections will give you coordinates that are symmetrically opposite to the original point in their respective axes.

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