1. $$ -3 p+q=0 $$ $$ 2 p-q=1 $$ Solve the following simultaneous linear equations using the matrix method.

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Solve the system of equations $$ -3p+q=0;2p-q=1 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}-3p+q=0\2p-q=1\end{array}ight.$$
- step1: Solve the equation:
  $$\left\{ \begin{array}{l}q=3p\2p-q=1\end{array}ight.$$
- step2: Substitute the value of $$q:$$
  $$2p-3p=1$$
- step3: Simplify:
  $$-p=1$$
- step4: Change the signs:
  $$p=-1$$
- step5: Substitute the value of $$p:$$
  $$q=3\left(-1ight)$$
- step6: Simplify:
  $$q=-3$$
- step7: Calculate:
  $$\left\{ \begin{array}{l}p=-1\q=-3\end{array}ight.$$
- step8: Check the solution:
  $$\left\{ \begin{array}{l}p=-1\q=-3\end{array}ight.$$
- step9: Rewrite:
  $$\left(p,qight) = \left(-1,-3ight)$$
The solution to the system of linear equations using the matrix method is $$ p = -1 $$ and $$ q = -3 $$.
$$ p = -1 $$ and $$ q = -3 $$.

Solve the following
simultaneous linear equations
using the matrix method.

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