6. Nitrification requires the addition of $$ 519 \mathrm{mg} / \mathrm{L} $$ of caustic soda. The c rate for the process is $$ 5 \mathrm{MGD}\left(18,925 \mathrm{~m}^{3} / \mathrm{day}\right) $$. What is the chemical A. $$ 19,410 \mathrm{lb} / $$ day $$ (8.812 \mathrm{ka} / \mathrm{d} $$

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To solve the problem, we need to calculate the total amount of caustic soda required for the nitrification process based on the given concentration and flow rate.

### Known Conditions:
1. Concentration of caustic soda: $$ 519 \, \text{mg/L} $$
2. Flow rate: $$ 5 \, \text{MGD} = 18,925 \, \text{m}^3/\text{day} $$

### Step-by-Step Calculation:

1. **Convert the concentration from mg/L to kg/m³**:
   $$
   1 \, \text{mg/L} = 0.001 \, \text{g/L} = 0.001 \, \text{kg/m}^3
   $$
   Therefore,
   $$
   519 \, \text{mg/L} = 519 \times 0.001 \, \text{kg/m}^3 = 0.519 \, \text{kg/m}^3
   $$

2. **Calculate the total mass of caustic soda required per day**:
   $$
   \text{Total mass} = \text{Concentration} \times \text{Flow rate}
   $$
   Substituting the values:
   $$
   \text{Total mass} = 0.519 \, \text{kg/m}^3 \times 18,925 \, \text{m}^3/\text{day}
   $$

3. **Perform the multiplication**:
   $$
   \text{Total mass} = 0.519 \times 18,925
   $$

Now, let's calculate this value.
Calculate the value by following steps:
- step0: Calculate:
  $$0.519\times 18925$$
- step1: Multiply the numbers:
  $$9822.075$$
The total mass of caustic soda required per day is approximately $$ 9822.075 \, \text{kg/day} $$.

4. **Convert kg/day to lb/day**:
   To convert kilograms to pounds, we use the conversion factor:
   $$
   1 \, \text{kg} = 2.20462 \, \text{lb}
   $$
   Therefore,
   $$
   \text{Total mass in lb/day} = 9822.075 \, \text{kg/day} \times 2.20462 \, \text{lb/kg}
   $$

Now, let's calculate this conversion.
Calculate the value by following steps:
- step0: Calculate:
  $$9822.075\times 2.20462$$
- step1: Multiply the numbers:
  $$21653.9429865$$
The total mass of caustic soda required per day is approximately $$ 21653.94 \, \text{lb/day} $$.

### Final Answer:
The chemical requirement for nitrification is approximately $$ 21653.94 \, \text{lb/day} $$.

This value does not match the provided option of $$ 19,410 \, \text{lb/day} $$. Please verify the input values or the expected output.
The chemical requirement for nitrification is approximately 21,654 pounds per day.

Nitrification requires the addition of of caustic soda. The c
rate for the process is . What is the chemical
A. day

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Nitrification requires the addition of of caustic soda. The c rate for the process is . What is the chemical A. day