6. Nitrification requires the addition of \( 519 \mathrm{mg} / \mathrm{L} \) of caustic soda. The c rate for the process is \( 5 \mathrm{MGD}\left(18,925 \mathrm{~m}^{3} / \mathrm{day}\right) \). What is the chemical A. \( 19,410 \mathrm{lb} / \) day \( (8.812 \mathrm{ka} / \mathrm{d} \)
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The Deep Dive
To convert the requirement of caustic soda from mg/L to lb/day, we start by calculating the total volume of water being treated each day. With a flow rate of 5 million gallons per day (MGD), we can use the conversion factor that 1 gallon is approximately 3.785 liters. Therefore, the volume in liters is \( 5,000,000 \text{ gallons} \times 3.785 \text{ L/gallon} \), which equals about 18,925,000 liters. Now, to find the daily amount of caustic soda in pounds, we multiply the concentration \( 519 \text{ mg/L} \) by the total volume in liters, giving us \( 519 \text{ mg/L} \times 18,925,000 \text{ L} \). First, convert mg to lb (1 mg = 0.00000220462 lb), and you’ll arrive at a final answer of approximately \( 19,410 \text{ lb/day} \). To verify, you can check the math step-by-step: calculate the total milligrams first, then convert to pounds. This method ensures you catch any potential miscalculations and reinforces the importance of double-checking with unit conversions, which is a common mistake in chemical calculations!