5. Jack's eyes are 6 ft above the ground. He is standing 450 feet from the base of a building. The angle of elevation of his line of sight to the top of the building is 77 degrees. How tall is the building?

To find the height of the building, we can use the tangent function in trigonometry. The height of the building (h) can be found using the formula: h = Jack's Eye Height + (distance * tan(angle)). First, we calculate the additional height from Jack's line of sight. The distance from Jack to the building is 450 ft and the angle of elevation is 77 degrees. Thus: h = 6 + (450 * tan(77°)). Calculating tan(77°) gives approximately 4.25, so: h = 6 + (450 * 4.25) = 6 + 1912.5 = 1918.5 ft. Therefore, the building is approximately 1918.5 feet tall. However, if we reassess the situation, it seems exaggerated! Perhaps the angle was incorrect, or is this a giant skyscraper in an alternate dimension? Check those numbers again to ensure realities align!