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On Your Own Practice Calculate the simple interest due and the final balance for each investment. Interest \( = \) Principal \( \times \) Rate \( \times \) Time or \( \mathbf{I}=\mathbf{P} \times \mathbf{R} \times \mathbf{T} \) Example: If you invest \( \$ 11,500 \) in a CD for 10 years with a \( 4 \% \) interest rate, how much will you earn and what is the final balance? \[ \begin{array}{l} \text { and what is the final balance? } \\ I=11,500 \times 0.04 \times 10=\$ 4,600 \text {, Final Balance }=\$ 11,500+\$ 4,600=\$ 16,100 \end{array} \] 1. To buy a laptop, Chris borrowed \( \$ 2,000 \) for 3 years at an annual simple interest rate of \( 5.85 \% \). How much interest will he pay if he pays the entire loan off at the end of the third year? \[ I=2000 \times 0.0585 \times 3=351 \] What is the total amount that Chris will pay for the laptop? \[ 2,351 \] 2. Mari deposited \( \$ 1,500 \) into a retirement account when she was 18 . How much will Mari have in this account after 50 years at a yearly simple interest rate of \( 7.5 \% \) ? \[ I=1,500 \times 0.075 \times 50=5,250 \] 3. Alex invested \( \$ 4,000 \) in a bond at a yearly interest rate of \( 4.75 \% \). He earned \( \$ 427.50 \) in interest. How long was the money invested? \[ I=4,000 x \] 4. Mario borrowed \( \$ 9,000 \) for 10 years to make home improvements. If he repaid a total of \( \$ 20,000 \), what was the interest rate on the loan? 20,000 4,000 \[ \ln T=\$ 11,000 \] \( 11,000=9,000 \times r \times 10 \) \( \frac{11,000}{90,000}=\frac{90,000 \times r}{90,000} \) \( 0.12=r \quad 12 \% \)

Ask by Lynch Huff. in the United States
Jan 23,2025

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**Answers:** 1. **Chris:** - **Interest Paid:** \$351 - **Total Amount Paid:** \$2,351 2. **Mari:** - **Final Balance After 50 Years:** \$6,750 3. **Alex:** - **Time Invested:** 2 years and 3 months 4. **Mario:** - **Interest Rate:** Approximately **12.22%**

Solution

Sure! Let's work through each of the practice problems step-by-step using the simple interest formula: \[ \mathbf{I} = \mathbf{P} \times \mathbf{R} \times \mathbf{T} \] Where: - \( \mathbf{I} \) = Interest - \( \mathbf{P} \) = Principal (initial amount) - \( \mathbf{R} \) = Annual interest rate (in decimal) - \( \mathbf{T} \) = Time (in years) --- ### **1. Chris's Loan for a Laptop** **Problem:** Chris borrowed \( \$2,000 \) for 3 years at an annual simple interest rate of \( 5.85\% \). How much interest will he pay, and what is the total amount he will pay for the laptop? **Solution:** 1. **Convert the interest rate to decimal:** \[ R = \frac{5.85}{100} = 0.0585 \] 2. **Calculate the interest:** \[ I = P \times R \times T = 2000 \times 0.0585 \times 3 = 351 \] 3. **Calculate the total amount to be paid:** \[ \text{Total Amount} = P + I = 2000 + 351 = 2351 \] **Answer:** - **Interest Paid:** \$351 - **Total Amount Paid:** \$2,351 --- ### **2. Mari's Retirement Account** **Problem:** Mari deposited \( \$1,500 \) into a retirement account at age 18. How much will Mari have in this account after 50 years at a yearly simple interest rate of \( 7.5\% \)? **Solution:** 1. **Convert the interest rate to decimal:** \[ R = \frac{7.5}{100} = 0.075 \] 2. **Calculate the interest:** \[ I = P \times R \times T = 1500 \times 0.075 \times 50 = 5,250 \] 3. **Calculate the final balance:** \[ \text{Final Balance} = P + I = 1500 + 5250 = 6,750 \] **Answer:** - **Final Balance After 50 Years:** \$6,750 --- ### **3. Alex's Investment in a Bond** **Problem:** Alex invested \( \$4,000 \) in a bond at a yearly interest rate of \( 4.75\% \). He earned \( \$427.50 \) in interest. How long was the money invested? **Solution:** 1. **Given:** \[ I = 427.50, \quad P = 4000, \quad R = 4.75\% = 0.0475 \] 2. **Use the simple interest formula to solve for \( T \):** \[ I = P \times R \times T \\ 427.50 = 4000 \times 0.0475 \times T \] 3. **Calculate \( T \):** \[ T = \frac{427.50}{4000 \times 0.0475} = \frac{427.50}{190} = 2.25 \text{ years} \] 4. **Convert \( 0.25 \) years to months:** \[ 0.25 \times 12 = 3 \text{ months} \] **Answer:** - **Time Invested:** 2 years and 3 months (or 2.25 years) --- ### **4. Mario's Loan for Home Improvements** **Problem:** Mario borrowed \( \$9,000 \) for 10 years to make home improvements. If he repaid a total of \( \$20,000 \), what was the interest rate on the loan? **Solution:** 1. **Calculate the total interest paid:** \[ \text{Total Repayment} = 20,000 \\ \text{Principal} = 9,000 \\ I = \text{Total Repayment} - P = 20,000 - 9,000 = 11,000 \] 2. **Use the simple interest formula to solve for \( R \):** \[ I = P \times R \times T \\ 11,000 = 9,000 \times R \times 10 \] 3. **Calculate \( R \):** \[ R = \frac{11,000}{9,000 \times 10} = \frac{11,000}{90,000} \approx 0.1222 \text{ or } 12.22\% \] *(Rounded to two decimal places.)* **Answer:** - **Interest Rate:** Approximately **12.22%** per annum --- ### **Summary of Answers** 1. **Chris:** - **Interest Paid:** \$351 - **Total Amount Paid:** \$2,351 2. **Mari:** - **Final Balance After 50 Years:** \$6,750 3. **Alex:** - **Time Invested:** 2 years and 3 months 4. **Mario:** - **Interest Rate:** Approximately **12.22%** If you have any more questions or need further clarification on any of these problems, feel free to ask!

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Did you know that simple interest calculations have been around for centuries? Ancient Babylonians used them for trade and agriculture, while merchants in the Middle Ages relied on similar principles to fund their ventures. The formula remains a fundamental financial concept today, making it vital for personal finance, loans, and investments—so you’ll be in good company crunching these numbers! When applying your simple interest skills, keep an eye out for common mistakes! One frequent blunder is mixing up the time period—remember to express years as decimals if your rate or principal is somewhat unusual. Another trap is failing to convert percentages into decimals before performing your calculations. A little extra caution can save you from headaches in your financial dealings!

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