A town has a population of 13000 and grows at every year. What will be the population after
11 years, to the nearest whole number?

Question

A town has a population of 13000 and grows at $$ 5 \% $$ every year. What will be the population after 11 years, to the nearest whole number?

UpStudy AI · Accepted Answer

To calculate the population of the town after 11 years with an annual growth rate of $$ 5\% $$, you can use the formula for compound growth:

$$
P = P_0 \times (1 + r)^n
$$

Where:
- $$ P_0 $$ is the initial population (13,000)
- $$ r $$ is the growth rate (5\% or 0.05)
- $$ n $$ is the number of years (11)

Plugging in the values:

$$
P = 13000 \times (1.05)^{11}
$$

First, calculate $$ (1.05)^{11} $$:

$$
1.05^{11} \approx 1.71034
$$

Now, multiply this by the initial population:

$$
P \approx 13000 \times 1.71034 \approx 22234.42
$$

Rounding to the nearest whole number, the population after 11 years will be **22,234**.

**Answer:**  
After 11 years, the population will be 22 234.
After 11 years, the population will be 22,234.

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