Divide. Leave your answer in exponent form. Assume that all variables in any denominator are nonzero. \( \frac{110 x^{5} y^{3}}{55 x^{2} y^{7}} \)

To divide the coefficients and the variables, start with the coefficients: \( \frac{110}{55} = 2 \). Now, divide the variable expressions: For \( x \), subtract the exponents: \( x^{5 - 2} = x^{3} \). For \( y \), again subtract the exponents: \( y^{3 - 7} = y^{-4} \). Putting it all together, we have: \[ 2 x^{3} y^{-4} \] In exponent form, it can also be rewritten as: \[ 2 x^{3} \frac{1}{y^{4}} \quad \text{or} \quad \frac{2 x^{3}}{y^{4}} \] So the final answer is \( 2 x^{3} y^{-4} \).