Multiply the special product. $$ (\sqrt{3}+y)(\sqrt{3}-y)=\square $$

Question

UpStudy AI · Accepted Answer

To multiply the special product $$(\sqrt{3} + y)(\sqrt{3} - y)$$, you can use the difference of squares formula:

$$
(a + b)(a - b) = a^2 - b^2
$$

Here, $$a = \sqrt{3}$$ and $$b = y$$. Applying the formula:

$$
(\sqrt{3} + y)(\sqrt{3} - y) = (\sqrt{3})^2 - y^2 = 3 - y^2
$$

**Answer:**
$$
3 - y^2
$$
$$ 3 - y^2 $$

Multiply the special product. \[ (\sqrt{3}+y)(\sqrt{3}-y)=\square \]