Determine if the following lengths make an acute, right or obtuse triangle. 8. \( 15,15,15 \sqrt{2} \).
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To determine the type of triangle formed by the lengths \( 15, 15, \) and \( 15\sqrt{2} \), we can use the triangle inequality and the properties of triangle types. First, let's confirm if these lengths can indeed form a triangle: - The sum of the lengths of any two sides must be greater than the length of the third side. 1. \( 15 + 15 > 15\sqrt{2} \) - \( 30 > 15\sqrt{2} \) (True, since \( \sqrt{2} \approx 1.414 \) thus \( 15\sqrt{2} \approx 21.21 \)) 2. \( 15 + 15\sqrt{2} > 15 \) - \( 15(1 + \sqrt{2}) > 15 \) (True, since \( 1 + \sqrt{2} > 1 \)) 3. \( 15 + 15\sqrt{2} > 15 \) - Same as above. Since all triangle inequalities hold true, \( 15, 15, \) and \( 15\sqrt{2} \) do indeed form a triangle. Next, we check the type of triangle: - For an acute triangle, all angles must be less than \( 90^\circ \). - For a right triangle, at least one angle is exactly \( 90^\circ \). - For an obtuse triangle, one angle is greater than \( 90^\circ \). To check for a right triangle, we can use the relationship for sides in right triangles where \( c^2 = a^2 + b^2 \). Here, let \( c = 15\sqrt{2} \) (the longest side) and \( a = 15, b = 15 \): - \( (15\sqrt{2})^2 = 15^2 + 15^2 \) - \( 450 = 225 + 225 \) - \( 450 = 450 \) Since the equality holds true, we conclude that the triangle is a right triangle.