Question
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se the imaginary number \( i \) to rewrite the expression below as a complex number. Simplify \( \sqrt{-39} \)

Ask by Vaughan Long. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

\[ \sqrt{-39} = \sqrt{39}\,i \]

Solution

To rewrite the expression \( \sqrt{-39} \) as a complex number using the imaginary unit \( i \), follow these steps: 1. **Understand the Imaginary Unit \( i \):** The imaginary unit \( i \) is defined as: \[ i = \sqrt{-1} \] 2. **Rewrite \( \sqrt{-39} \):** Use the property of square roots involving negative numbers: \[ \sqrt{-39} = \sqrt{39} \cdot \sqrt{-1} = \sqrt{39} \cdot i \] 3. **Express as a Complex Number:** A complex number is generally written in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. In this case, there is no real part, so \( a = 0 \): \[ \sqrt{-39} = 0 + \sqrt{39}i \] However, it's common to simply write it as: \[ \sqrt{39}i \] **Final Answer:** \[ \sqrt{-39} = \sqrt{39}\,i \]

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To rewrite \( \sqrt{-39} \) using the imaginary unit \( i \), you can express it as follows: \[ \sqrt{-39} = \sqrt{39} \cdot \sqrt{-1} = \sqrt{39} \cdot i = i\sqrt{39}. \] Thus, the expression simplifies to \( i\sqrt{39} \), where \( i \) represents the square root of -1, turning this initially troublesome square root into a manageable complex number. If you need to perform operations with this complex number, remember that multiplying or dividing by \( i \) can be a fun twist! For example, multiplying \( i\sqrt{39} \) by \( i \) results in \( -39 \), converting it back to a real number. The interplay between real and imaginary numbers opens up new possibilities in mathematics!

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