Question
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Two sides of a triangle measure \( 2 x-4 \) and \( 7 x-2 \) units, respectively. Which of these is a possible length for the third side of the triangle? A \( 3 x \) units B \( 6 x \) units \( 5 x+2 \) units D \( 9 x-6 \) units Check Answer

Ask by Lowe Hamilton. in the United States
Jan 21,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The possible length for the third side is \(6x\) units.

Solution

To determine which option represents a possible length for the third side of the triangle, we'll use the **triangle inequality theorem**. This theorem states that for any triangle, the sum of the lengths of any two sides must be greater than the length of the remaining side. Given: - Side \( a = 2x - 4 \) - Side \( b = 7x - 2 \) - Third side \( c \) is one of the options: \( 3x \), \( 6x \), \( 5x + 2 \), or \( 9x - 6 \) **Step 1: Ensure Positive Lengths** First, ensure that all sides are positive: 1. \( 2x - 4 > 0 \) → \( x > 2 \) 2. \( 7x - 2 > 0 \) → \( x > \frac{2}{7} \) Since \( x > 2 \) is more restrictive, we'll use that. **Step 2: Apply the Triangle Inequality** For sides \( a \), \( b \), and \( c \), the following must hold: 1. \( a + b > c \) 2. \( a + c > b \) 3. \( b + c > a \) Let's determine the range for \( c \): - \( a + b = (2x - 4) + (7x - 2) = 9x - 6 \) - \( |a - b| = |2x - 4 - (7x - 2)| = | -5x - 2 | = 5x + 2 \) Thus, the third side \( c \) must satisfy: \[ 5x + 2 < c < 9x - 6 \] **Step 3: Evaluate Each Option** 1. **Option A: \( 3x \)** - Check \( 5x + 2 < 3x \): \[ 5x + 2 < 3x \Rightarrow 2x < -2 \Rightarrow x < -1 \] But \( x > 2 \), so **invalid**. 2. **Option B: \( 6x \)** - Check \( 5x + 2 < 6x \): \[ 5x + 2 < 6x \Rightarrow x > 2 \] - Check \( 6x < 9x - 6 \): \[ 6x < 9x - 6 \Rightarrow 3x > 6 \Rightarrow x > 2 \] - Both conditions are satisfied for \( x > 2 \). **Valid**. 3. **Option C: \( 5x + 2 \)** - Check \( 5x + 2 < 5x + 2 \): - This is not true as it results in an equality. **Invalid**. 4. **Option D: \( 9x - 6 \)** - Check \( 9x - 6 < 9x - 6 \): - This is not true as it results in an equality. **Invalid**. **Conclusion:** Only **Option B: \( 6x \) units** satisfies the triangle inequality conditions for \( x > 2 \). **Answer:** B) \(6x\) units

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The Deep Dive

To find a possible length for the third side of the triangle, we can use the triangle inequality theorem. This states that the sum of the lengths of any two sides must be greater than the length of the third side. Let the sides be \( a = 2x - 4 \) and \( b = 7x - 2 \). We need to consider each option for the third side \( c \): 1. For \( c = 3x \): - \( (2x - 4) + (7x - 2) > 3x \) simplifies to \( 9x - 6 > 3x \), which gives \( 6x > 6 \) or \( x > 1 \). - \( (2x - 4) + 3x > (7x - 2) \) simplifies to \( 5x - 4 > 7x - 2 \), leading to \( -4 > 2x - 2 \), giving \( x < 1 \). - However, these two inequalities contradict each other, so \( 3x \) is not a possible side. 2. For \( c = 6x \): - \( (2x - 4) + (7x - 2) > 6x \) simplifies to \( 9x - 6 > 6x \), or \( 3x > 6 \), yielding \( x > 2 \). - \( (2x - 4) + 6x > (7x - 2) \) simplifies to \( 8x - 4 > 7x - 2 \), leading to \( x > 2 \). - Both give \( x > 2 \), so \( 6x \) is possible. 3. For \( c = 5x + 2 \): - \( (2x - 4) + (7x - 2) > 5x + 2 \) simplifies to \( 9x - 6 > 5x + 2 \), which gives \( 4x > 8 \) or \( x > 2 \). - \( (2x - 4) + (5x + 2) > (7x - 2) \) simplifies to \( 7x - 2 > 7x - 2 \), which is always true. - However, the first condition requires \( x > 2 \), so \( 5x + 2 \) is also possible. 4. For \( c = 9x - 6 \): - \( (2x - 4) + (7x - 2) > 9x - 6 \) simplifies to \( 9x - 6 > 9x - 6 \), which is always true. - However, this condition doesn’t help in enforcing a boundary for \( x \). Considering the inequalities derived from the triangle inequality theorem, \( 6x \) and \( 5x + 2 \) are both valid options. However, as per the question, we pick only one possible length for the third side, leading us to conclude that at least \( 6x \) units is a solid candidate based on all conditions met. The third side can be \( 6x \) units.

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