Find the $$ x $$ - and $$ y $$-intercepts of the line $$ 3 x+6 y=-18 $$. Write your answers as integers or as simplified proper or improper fractions, not as ordered pairs. $$ x \text {-intercept: } $$ $$ \quad y $$-intercept:

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To find the $$ x $$-intercept, we set $$ y=0 $$ in the equation and solve for $$ x $$.

1. Given the equation:
   $$
   3x + 6y = -18
   $$
2. Set $$ y=0 $$:
   $$
   3x + 6(0) = -18 \quad \Longrightarrow \quad 3x = -18
   $$
3. Solve for $$ x $$:
   $$
   x = \frac{-18}{3} = -6
   $$
   
Thus, the $$ x $$-intercept is:
$$
\boxed{-6}
$$

To find the $$ y $$-intercept, we set $$ x=0 $$ in the equation and solve for $$ y $$.

1. Starting with the same equation:
   $$
   3x + 6y = -18
   $$
2. Set $$ x=0 $$:
   $$
   3(0) + 6y = -18 \quad \Longrightarrow \quad 6y = -18
   $$
3. Solve for $$ y $$:
   $$
   y = \frac{-18}{6} = -3
   $$
   
Thus, the $$ y $$-intercept is:
$$
\boxed{-3}
$$
$$ x $$-intercept: -6 $$ y $$-intercept: -3

Find the - and -intercepts of the line .
Write your answers as integers or as simplified proper or improper fractions, not as ordered
pairs.

-intercept:

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Find the - and -intercepts of the line . Write your answers as integers or as simplified proper or improper fractions, not as ordered pairs. -intercept: