If : \( f(X)=2 X+b \) and \( g(X)=\mathrm{b} \) where \( f, g \) from the polynomial functions and \( f(1)+g(4)=12 \) Find the value of : \( f(4)+g(-1) \)
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To solve for \( f(4) + g(-1) \), we begin with the given functions: \[ f(X) = 2X + b \] \[ g(X) = b \] Next, we use the equation provided: \[ f(1) + g(4) = 12 \] First, we calculate \( f(1) \) and \( g(4) \): \[ f(1) = 2(1) + b = 2 + b \] \[ g(4) = b \] Now substituting these into the equation: \[ (2 + b) + b = 12 \] Simplifying this: \[ 2 + 2b = 12 \] Subtracting 2 from both sides: \[ 2b = 10 \] Dividing by 2: \[ b = 5 \] Now that we have \( b \), we can find \( f(4) \) and \( g(-1) \): Calculating \( f(4) \): \[ f(4) = 2(4) + b = 8 + 5 = 13 \] Calculating \( g(-1) \): \[ g(-1) = b = 5 \] Finally, we add \( f(4) \) and \( g(-1) \): \[ f(4) + g(-1) = 13 + 5 = 18 \] Thus, the value of \( f(4) + g(-1) \) is: \[ \boxed{18} \]