Which is performing more efficiently, a car getting 12 km per liter of gas or one getting 31 miles per gallon of gas? Choose the correct answer below. \( \begin{array}{l}31 \mathrm{mi} / \mathrm{gal} \\ 12 \mathrm{~km} / l i t e r \\ \text { Both are performing equally. }\end{array} \)

To determine which car is performing more efficiently, we need to convert both fuel efficiency measurements to the same unit. We can convert miles per gallon (mpg) to kilometers per liter (km/l) or vice versa. 1. **Convert 31 miles per gallon to kilometers per liter:** - 1 mile = 1.60934 kilometers - 1 gallon = 3.78541 liters Using these conversions, we can calculate the efficiency in km/l: \[ \text{Efficiency in km/l} = \left(31 \text{ miles/gal}\right) \times \left(\frac{1.60934 \text{ km}}{1 \text{ mile}}\right) \times \left(\frac{1 \text{ gal}}{3.78541 \text{ liters}}\right) \] 2. **Calculate the efficiency:** Let's perform the calculation. \[ \text{Efficiency in km/l} = 31 \times \frac{1.60934}{3.78541} \] Now, I will calculate this value. Calculate the value by following steps: - step0: Calculate: \(31\left(\frac{1.60934}{3.78541}\right)\) - step1: Divide the terms: \(31\times \frac{160934}{378541}\) - step2: Reduce the numbers: \(1\times \frac{160934}{12211}\) - step3: Multiply: \(\frac{160934}{12211}\) The calculation gives us an efficiency of approximately \( 13.18 \, \text{km/l} \) for the car that gets 31 miles per gallon. Now we can compare the two efficiencies: - Car A: \( 12 \, \text{km/l} \) - Car B: \( 13.18 \, \text{km/l} \) Since \( 13.18 \, \text{km/l} \) (Car B) is greater than \( 12 \, \text{km/l} \) (Car A), we can conclude that: **The car getting 31 miles per gallon is performing more efficiently.**