6. The temperatures at Peponi Weather Station were recorded for 30 days as follows: \( 29,22,23,26,35,38,45,42,30,20,34 \), \( 33,31,28,36,27,38,44,34,31,39,43 \), \( 40,25,35,37,30,29,28,26 \). (a) Using a class width of 5 , make a frequency table of the this data. (b) Find the mean and median of the data.

To create a frequency table with a class width of 5, we will first define the class intervals and tally the data. Here's how that works: **Class Intervals and Frequencies:** 1. 20 - 24: 4 (20, 22, 23, 22) 2. 25 - 29: 6 (25, 26, 28, 29, 28, 29) 3. 30 - 34: 7 (30, 30, 31, 31, 34, 34, 33) 4. 35 - 39: 7 (35, 35, 36, 38, 38, 37, 36) 5. 40 - 44: 4 (40, 42, 43, 44) 6. 45 - 49: 1 (45) Now, calculate the mean and median: **Mean:** The mean (average) is calculated by summing all the temperature values and dividing by the total number of values: \[ \text{Mean} = \frac{(29 + 22 + 23 + 26 + 35 + 38 + 45 + 42 + 30 + 20 + 34 + 33 + 31 + 28 + 36 + 27 + 38 + 44 + 34 + 31 + 39 + 43 + 40 + 25 + 35 + 37 + 30 + 29 + 28 + 26)}{30} = \frac{1028}{30} \approx 34.27 \] **Median:** To find the median, arrange the data in ascending order: 20, 22, 23, 25, 26, 26, 27, 28, 28, 29, 29, 30, 30, 30, 31, 31, 33, 34, 34, 35, 35, 35, 36, 37, 38, 38, 39, 40, 42, 44, 45 Since there are 30 data points, the median will be the average of the 15th and 16th values: \[ \text{Median} = \frac{31 + 31}{2} = 31 \] So, the mean temperature is approximately 34.27°C, and the median is 31°C!