3) \( 14 \cdot 2-2+[20-5 \cdot(12-4 \cdot 2)] \cdot(8+10)= \)

To solve the expression \( 14 \cdot 2-2+[20-5 \cdot(12-4 \cdot 2)] \cdot(8+10) \), let's break it down step by step: 1. **Calculate the multiplication and parentheses:** - \( 14 \cdot 2 = 28 \) - \( 4 \cdot 2 = 8 \) so \( 12 - 8 = 4 \) - \( 5 \cdot 4 = 20 \) 2. **Now plug these values back into the expression:** - \( 20 - 20 = 0 \) 3. **Next, evaluate the addition in parentheses:** - \( 8 + 10 = 18 \) 4. **Now, substitute back into the expression:** - The expression simplifies to \( 28 - 2 + [0] \cdot 18 \) 5. **Final Evaluation:** - Since multiplying by 0 gives us 0, we have \( 28 - 2 + 0 = 26 \) Thus, the result is \( 26 \).