Find the real solutions, if any, of the following equation. Use the quadratic formula. Select the correct choice below and, if necessary, fill in the answer box to complete your answer. A. The solution set is \( \} \). (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) B. The solution is not a real number.

To solve a quadratic equation using the quadratic formula, \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), first identify the coefficients \(a\), \(b\), and \(c\) from your equation \(ax^2 + bx + c = 0\). If the discriminant (\(b^2 - 4ac\)) is positive, you'll get two distinct real solutions; if it equals zero, there's one real solution; and if it's negative, there are no real solutions. When applying the quadratic formula, keep an eye out for common mistakes like miscalculating \(b^2\) or forgetting to simplify your radical. Always check that you’ve accounted for all terms in the quadratic and have accurately computed the discriminant to determine the nature of your solutions. Happy solving!