If $$ \log _{2}(3 x-2)=4 $$, then what is the value of $$ x $$ ? a.) 2 b.) 6 c.) 3 d.) 4

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To solve the equation $$ \log _{2}(3x - 2) = 4 $$, follow these steps:

1. **Understand the logarithmic equation:**  
   The equation $$ \log_b(a) = c $$ is equivalent to $$ a = b^c $$.  
   Applying this to the given equation:  
   $$ 3x - 2 = 2^4 $$

2. **Calculate $$ 2^4 $$:**  
   $$ 2^4 = 16 $$  
   So,  
   $$ 3x - 2 = 16 $$

3. **Solve for $$ x $$:**  
   $$ 3x = 16 + 2 $$  
   $$ 3x = 18 $$  
   $$ x = \frac{18}{3} $$  
   $$ x = 6 $$

**Answer:**  
**b.) 6**
$$ x = 6 $$

If , then what is the value of ?
a.) 2
b.) 6
c.) 3
d.) 4

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