Solve the inequality and graph the solution on the number line. \( 3 x+6<2 x+8 \) or \( 2 x+4 \leq 4 x-6 \)
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To solve the first part of the inequality \( 3x + 6 < 2x + 8 \), subtract \(2x\) from both sides to get \(x + 6 < 8\). Then, subtract \(6\) from both sides, yielding \(x < 2\). For the second inequality \( 2x + 4 \leq 4x - 6 \), start by subtracting \(2x\) from both sides to obtain \(4 \leq 2x - 6\). Adding \(6\) to both sides gives \(10 \leq 2x\), or dividing by \(2\) results in \(5 \leq x\) or \(x \geq 5\). Combining both parts, the solution set is \( x < 2\) or \( x \geq 5\). On the number line, you would show an open circle at \(2\) with a line extending leftward, and a closed circle at \(5\) with a line extending rightward. Now you can easily tell where the solutions lie, coloring in the number line just like a fun art project! Just remember, one part of your solution loves to hang out until 2 (but not including it), while the other part can rule the world from 5 onwards.